8 Answers

• Code (generates a number between 0 and 99, ):

  var randomnumber = 0;
  
  for(var i = 0; i < 20; i++){
      randomnumber=Math.floor(Math.random()*100);
      Ti.API.info("random: " + i + " / " + randomnumber);
  }
  

  Output:

  [INFO] random: 0 / 38
  [INFO] random: 1 / 90
  [INFO] random: 2 / 40
  [INFO] random: 3 / 41
  [INFO] random: 4 / 3
  [INFO] random: 5 / 96
  [INFO] random: 6 / 32
  [INFO] random: 7 / 75
  [INFO] random: 8 / 17
  [INFO] random: 9 / 73
  [INFO] random: 10 / 24
  [INFO] random: 11 / 17
  [INFO] random: 12 / 65
  [INFO] random: 13 / 33
  [INFO] random: 14 / 30
  [INFO] random: 15 / 6
  [INFO] random: 16 / 32
  [INFO] random: 17 / 82
  [INFO] random: 18 / 51
  [INFO] random: 19 / 99
  

• Nobody here has any clue?

  Maybe we should try something different.
  Instead of a random function, how about a shuffle?

  Let us define the numbers and data for that number and let a function shuffle those around then output them accordingly.

  Any anwser for random is still welcome though.

• Hi Patrick,
  I cut/pasted and ran the code you have above, and at least on the simulator I don't see the first 5 numbers always the same as you reported. Gregor Munro had a nice post on this thread (http://developer.appcelerator.com/question/20901/random-number-bug) with a method for generating random numbers in a given range.

• I know you have tried many things, maybe even the one I am providing, but it seems to have worked pretty well for me and isn't an obvious choice…..

  randomnumber = new Date().getTime() % (highestNumberWanted + 1);

  Though this may not work so well in your case, being as you are continually looping…though you could throw some more randomness into it.

• I spent hours pulling my hair out over this one.

  The solution I came up with was to generate a string of random numbers, then reverse the string, and pull the data from the front of the string.

  
  str = str.reverse();
  

• What about …

                  for (var z=0;z<30;z++)    
          {
              var chars = "0123456789ABCDEF";
              var string_length = 16;
              var randomstring = '';
              for (var i=0; i<string_length; i++) {
                  var rnum = Math.floor(Math.random() * chars.length);
                  randomstring += chars.substring(rnum,rnum+1);
              }
              var row = Ti.UI.createTableViewRow({height:50, hasCheck:false});
              var l1 = Ti.UI.createLabel({text:randomstring, font:{fontSize:14}, color:'#324892', left:10});
              row.add(l1);
              data.push(row);
          }
  

• 
  var live=new Date();
  live=live.toString();
  var myhash=Titanium.Utils.md5HexDigest(live);
  

• I have no way to justify this solution, but it works for me. Going along with the trend of the first 5 are the same, just call a function 5 times to get them out of the way and the rest actually appear to be random every time.

  function genRandNum(max){ //could be more robust, this returns (zero through max) return Math.floor(Math.random()*(max-1)); }

  then hack in this above your script:

  var null_rand1 = genRandNum(10); var null_rand2 = genRandNum(10); var null_rand3 = genRandNum(10); var null_rand4 = genRandNum(10); var null_rand5 = genRandNum(10);

  no idea why, but works in my app.